an explanation of hubble redshift due to the global non-holonomity of space
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ID: 172333
2009
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Abstract
In General Relativity, the change of the energy of a freely moving photon should be the solution to the scalar equation of the isotropic geodesic equations, which manifests the work produced on the photon being moved along the path. I solved the equation in terms of physical observables (Zelmanov, Physics Doklady, 1956, v.1, 227-230), and in the large scale approximation, i.e. with gravitation and deformation neglected in the space, while supposing the isotropic space to be globally non-holonomic (the time lines are non-orthogonal to the spatial section, a condition manifested by the rotation of the space). The solution is $E = E_{0} exp(-Omega^{2} at/c$), where $Omega$ is the angular velocity of the space (it meets the Hubble constant $H_{0} = c/a = 2.3 imes 10^{-18}$ s$^{-1}$), $a$ is the radius of the Universe, $t = r/c$ is the time of the photon's travel. So a photon loses energy with distance due to the work against the field of the space non-holonomity. According to the solution, the redshift should be $z = exp(H_{0} r/c) - 1 = H_{0} r/c$. This solution explains both the redshift $z = H_{0} r/c$ observed at small distances and the non-linearity of the empirical Hubble law due to the exponent (at large $r$). The ultimate redshift, according to the theory, should be $z = exp(pi ) - 1 = 22.14$.
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| Authors | ;Rabounski D. |
| Journal | e-jurnal akuntansi |
| Year | 2009 |
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